2020-05-14T16:43:10-04:00
The loss due to an earthquake in a commercial building is modelled by a random variable X with density function
1
2020-05-15T17:48:40-0400
Compute
P ( X > 18 ∣ X > 10 ) = P ( X > 18 ) P ( X > 10 ) P(X>18|X>10)={P(X>18)\over P(X>10)} P ( X > 18∣ X > 10 ) = P ( X > 10 ) P ( X > 18 )
P ( X > 10 ) = ∫ 10 ∞ f ( x ) d x = ∫ 10 20 0.005 ( 20 − x ) d x = P(X>10)=\displaystyle\int_{10}^{\infin}f(x)dx=\displaystyle\int_{10}^{20}0.005(20-x)dx= P ( X > 10 ) = ∫ 10 ∞ f ( x ) d x = ∫ 10 20 0.005 ( 20 − x ) d x =
= 0.005 [ 20 x − x 2 2 ] 20 10 = 0.005 ( 400 − 200 − ( 200 − 50 ) ) = =0.005\bigg[20x-{x^2\over 2}\bigg]\begin{matrix}
20 \\
10
\end{matrix}=0.005(400-200-(200-50))= = 0.005 [ 20 x − 2 x 2 ] 20 10 = 0.005 ( 400 − 200 − ( 200 − 50 )) =
= 0.25 =0.25 = 0.25
P ( X > 18 ) = ∫ 18 ∞ f ( x ) d x = ∫ 18 20 0.005 ( 20 − x ) d x = P(X>18)=\displaystyle\int_{18}^{\infin}f(x)dx=\displaystyle\int_{18}^{20}0.005(20-x)dx= P ( X > 18 ) = ∫ 18 ∞ f ( x ) d x = ∫ 18 20 0.005 ( 20 − x ) d x =
= 0.005 [ 20 x − x 2 2 ] 20 18 = 0.005 ( 400 − 200 − ( 360 − 162 ) ) = =0.005\bigg[20x-{x^2\over 2}\bigg]\begin{matrix}
20 \\
18
\end{matrix}=0.005(400-200-(360-162))= = 0.005 [ 20 x − 2 x 2 ] 20 18 = 0.005 ( 400 − 200 − ( 360 − 162 )) =
= 0.01 =0.01 = 0.01
P ( X > 18 ∣ X > 10 ) = P ( X > 18 ) P ( X > 10 ) = 0.01 0.25 = 0.04 P(X>18|X>10)={P(X>18)\over P(X>10)}={0.01\over 0.25}=0.04 P ( X > 18∣ X > 10 ) = P ( X > 10 ) P ( X > 18 ) = 0.25 0.01 = 0.04
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