(i) the player winning both tournaments:
P=P(winning I tournament)*P(winning II tournament after winning I tournament)=0.6*0.65=0.39
(ii) the player winning at least one tournament:
P=1- P(lose I tour. and lose II tour.)=1- (1-0.6)*(1-0.5)=1-0.2=0.8=80%
Comments
Leave a comment