H0: μ =100
H1: μ >100
α=0.01
t=(x -μ)/(s/√n)→(120-100)/(15/√6)=3.26
From t table, a t of 3.26 correspond to a p -value to the right of 0.0112
Therefore, since p > .0112, there is no evidence to suggest that the mean is higher. As such, the test does not support the doctor’s claim.
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