Null hypothesis "H_0:p=0.6."
Alternative hypothesis "H_a:p\\ne 0.6."
Test statistic: "z=\\frac{\\hat p-p}{\\sqrt{\\frac{p(1-p)}{n}}}=\\frac{0.58-0.6}{\\sqrt{\\frac{0.6(1-0.6)}{500}}}=-0.91."
P-value: "p=0.3628."
Since P-value is greater than 0.10, fail to reject the null hypothesis.
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