Question #115129
A hospital receives 20% of its COVID-19 vaccine shipments from Ghana and the remainder of its shipments from neighbouring countries. Each shipment contains a very large number of vaccine vials. For Ghana’s shipments, 10% of the vials are ineffective. For the neighbouring countries, 2% of the vials are ineffective. The hospital tests 30 randomly selected vials from a shipment and finds that one is ineffective. What is the probability that the shipment came from Ghana.
1
Expert's answer
2020-05-11T18:11:51-0400

Let G=G= the event that the shipment is from Ghana. Then GCG^C is the event that the shipment is from neighbouring countries.

Given


P(G)=0.2P(G)=0.2

Then


P(GC)=1P(G)=10.2=0.8P(G^C)=1-P(G)=1-0.2=0.8

Let I=I= be the event that the vial is ineffective.

Use binomial distribution.


P(X=x)=(nx)px(1p)nxP(X=x)=\binom{n}{x}p^x(1-p)^{n-x}

Find the probability that one out of 30 vials is ineffective, given that the shipment is from Ghana

n=30,p=0.1,x=1n=30, p=0.1,x=1


P(IG)=(301)(0.1)1(10.1)3010.14130386P(I|G)=\binom{30}{1}(0.1)^1(1-0.1)^{30-1}\approx0.14130386

Find the probability that one out of 30 vials is ineffective, given that the shipment is from neighbouring countries

n=30,p=0.02,x=1n=30, p=0.02,x=1


P(IGC)=(301)(0.02)1(10.02)3010.333970P(I|G^C)=\binom{30}{1}(0.02)^1(1-0.02)^{30-1}\approx0.333970

We are looking for P(GI).P(G|I). Use Bayes' Theorem


P(GI)=P(IG)P(G)P(IG)P(G)+P(IGC)P(GC)P(G|I)={P(I|G)P(G)\over P(I|G)P(G)+P(I|G^C)P(G^C)}\approx

0.14130386(0.2)0.14130386(0.2)+0.333970(0.8)0.0957\approx{0.14130386(0.2)\over0.14130386(0.2)+0.333970(0.8)}\approx0.0957

P(GI)=0.0957P(G|I)=0.0957


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