Question

B1. Suppose that 3% of computer chips produced by a certain machine are defective. The
chips are put into packages of 20 chips for distribution to retailers. What is the
probability that a randomly selected package of chips will contain at least 2 defective
chips?

Answer 1

n=20,p=0.03

P(x≥2)=1-P(x=0)-P(x=1)

P(x=0)=C_20,0*0.03⁰*(1-0.03)^20-0=0.5438

P(x=1)=C_20,1*0.03¹*0.97¹⁹=0.3363

P(x≥2)=1-0.5438-0.3363=0.12