Answer to Question #114156 in Statistics and Probability for Nimra

Question

Distance =14,23,9,17,10,22,5,12,6,10. Charges= 68,105,40,79,81,95,31,72,45,93.
Required following.
1) coefficient of correlation
2) coefficient of determination
3) probable Error
4) Interpretation

Answer 1

1) X Values: ∑ = 128,Mean = 12.8

∑(X - M_x)² = SS_x = 345.6

Y Values: ∑ = 709,Mean = 70.9

∑(Y - M_y)² = SS_y = 5626.9

X and Y Combined

N = 10

∑(X - M_x)(Y - M_y) = 1113.8

r = ∑((X - M_y)(Y - M_x)) / $\sqrt{((SSx)(SSy))}$

r = 1113.8 / $\sqrt{((345.6)(5626.9))}$ = 0.7987

2) cd=r²=0.63793

3)using formula (where 0.674 - const): e=0.674 *(1-r²) /$\sqrt{N}$ =0.07717

​4)A strong uphill (positive) linear relationship