Question #113698
QUESTIONS 1, 2 AND 3 ARE BASED ON THE FOLLOWING INFORMATION.

Around elections time the number of daily fake news posts about politicians follows the following discrete probability distribution.

x 0 1 2 3 4
P (X = x) 0.1 0.15 0.2 0.25 ?

Let X be the number of daily fake news posts.

Question 1

Which one of the following statements is incorrect?

(1) ∑_ P(x) = 1
(2) P(X = 4) = 0
(3) P(X ≤ 4) = 1
(4) P(X ≥ 4) = 0.3
(5) None of the above.

Question 2

What is the expected number of daily fake news posts about politicians around elections time?

(1) 5.3
(2) 4
(3) 2.5
(4) 2.1
(5) 1.3


Question 3

What is the standard deviation of daily fake news posts about politicians around election time?

(1) 1.32
(2) 1.75
(3) 2.5
(4) 1
(5) None of the above
1
Expert's answer
2020-05-11T13:33:49-0400

since x=04P(X=x)=1\sum\limits_{x=0}^{4}P(X=x) =1

therefore P(X=4)=1(0.1+0.15+0.2+0.25)=0.3P(X=4)=1-(0.1+0.15+0.2+0.25)=0.3

therefore ,

In Question 01,

answer is (2)

P(X=4)=0P(X=4)=0 is incorrect and correct one is P(X=4)=0.3P(X=4)=0.3


In Question 02,

expected number E[X],

E[X]=i=04xP(X=x)E[X]=00.1+10.15+20.2+30.25+40.3E[X]=2.5E[X]=\sum\limits_{i=0}^{4}xP(X=x)\\ E[X]=0*0.1+1*0.15+2*0.2\\\hspace {4 em}+3*0.25+4*0.3\\ E[X]=2.5

answer is (3)


In Question 03,

standard deviation =variance=V(X)\sqrt{variance}=\sqrt{V(X)}

V(X)=E[X2]E[X]2E[X2]=i=04x2P(X=x)E[X2]=020.1+120.15+220.2+320.25+420.3E[X2]=8V(X)=82.52=1.75standard deviation=1.75=1.322V(X)=E[X^2]-E[X]^2\\ E[X^2]=\sum\limits_{i=0}^{4}x^2P(X=x)\\ E[X^2]=0^2*0.1+1^2*0.15+2^2*0.2\\\hspace {4 em}+3^2*0.25+4^2*0.3\\ E[X^2]=8\\ V(X)=8-2.5^2=1.75\\ standard\ deviation=\sqrt{1.75}=1.322

answer is (1)



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