Answer to Question #113394 in Statistics and Probability for Ruth Mutale Chutu

Question

The manager of the lodge has found that about 10% of the parties who make reservations
do not show up. If 120 party observations have been made,
(i) How many can be expected to show up?
(ii) Find the variance of this distribution.
(iii) Find the standard deviation of this distribution.

Answer 1

Probability that party show up: P=100-10=90%=0.9

1) E(x)=n*p=120*0.9=108

2)Var(x)=npq=120*0.9*0.1=10.8

3)σ= $\sqrt{{Var(x)}}= ​$ 3.2863