Answer to Question #11255 in Statistics and Probability for Ke_091

Question

(a) A group of 5 boys and 4 girls are to be photographed. In how many ways can they be arranged such that:

(i) No two girls sit together?

(ii) No two boys sit together?

Answer 1

(i) we have at least this formation gbgbgbg
g- girl, b – boy.
2 boys that left can sit at random – there are 8*8=64 variants.

(ii) No two boys sit together
There is only one variant for this case
bgbgbgbgb
where b-boy, g-girl.
so answer equals& 1