If there are 3 female students out of 10, the probability of a student being female 0.3.
This is a binomial distribution case.
P(X =x) ="{n \\choose x } p^x(1-p)^{n-x}"
Let x be the event that a student is female.
n=20, x=14, p=0.3
P(X=14)="{20 \\choose 14}*0.3^{14}*(1-0.3)^6"
=0.0002181
Comments
Leave a comment