Y=a+bxY=a+bxY=a+bx
a=(∑y∑x2)−(∑x∑xy)n∑x2−(∑x)2a=\frac{(\sum y \sum x^2)-(\sum x \sum xy)}{n\sum x^2-(\sum x)^2}a=n∑x2−(∑x)2(∑y∑x2)−(∑x∑xy)
a=(−55.4726×390)−(52×(−681.361))(13×390)−522=5.8311a=\frac{(-55.4726×390)-(52×(-681.361))}{(13×390)-52^2}=5.8311a=(13×390)−522(−55.4726×390)−(52×(−681.361))=5.8311
b=n∑xy−∑x∑yn∑x2−(∑x)2b=\frac{n\sum xy-\sum x \sum y}{n\sum x^2-(\sum x)^2}b=n∑x2−(∑x)2n∑xy−∑x∑y
b=(13×(−681.361))−(52×(−55.4726))(13×390)−522=−2.5246b=\frac{(13×(-681.361))-(52×(-55.4726))}{(13×390)-52^2}=-2.5246b=(13×390)−522(13×(−681.361))−(52×(−55.4726))=−2.5246
Thus, Y=5.8311−2.5246xY=5.8311-2.5246xY=5.8311−2.5246x
The correct choice is (c).
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