Answer to Question #110110 in Statistics and Probability for Mateus Michael Ndinomwene

Question #110110

The mean diameter of a population of newly settled periwinkle is 8.5 cm with a standard deviation of 1.10 cm. What is the probability of selecting a random sample of 100 wrinkles that has a mean diameter greater than 8.52.

Expert's answer

"P(\\bar X>8.52)=P(Z>\\frac{\\bar x-\\mu}{\\frac{\\sigma}{\\sqrt{n}}})=P(Z>\\frac{8.52-8.5}{\\frac{1.10}{\\sqrt{100}}})=P(Z>0.18)=0.4286."

Learn more about our help with Assignments: Statistics and Probability

Comments

Assignment Expert

17.04.20, 16:39

Dear Mateus Michael Ndinomwene, You are welcome. We are glad to be helpful. If you liked our service, please press a like-button beside the answer field. Thank you!

Mateus Michael Ndinomwene

17.04.20, 05:29

Thank you so much this is really helping me especially this time of online learning.

Answer to Question #110110 in Statistics and Probability for Mateus Michael Ndinomwene

Comments

Leave a comment

Related Questions