i. This is a binomial distribution with p=0.2, n=5.
"P(X=0)=C^0_5p^0(1-p)^5=(1-0.2)^5=0.32768."
ii. "P(X=4)=C^4_5p^4(1-p)^1=5*0.2^4*(1-0.2)^1=0.0064."
iii. "P(X=5)=C^5_5p^5(1-p)^0=0.2^5=0.00032."
iv. "P(X\\ge3)=P(X=3)+P(X=4)+P(X=5)="
"=C^3_5p^3(1-p)^2+C_5^4p^4(1-p)^1+C_5^5p^5(1-p)^0="
"=10*0.2^3*(1-0.2)^2+5*0.2^4+(1-0.2)^1+0.2^5=0.05792."
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