i. This is a binomial distribution with p=0.2, n=5.
P(X=0)=C50p0(1−p)5=(1−0.2)5=0.32768.
ii. P(X=4)=C54p4(1−p)1=5∗0.24∗(1−0.2)1=0.0064.
iii. P(X=5)=C55p5(1−p)0=0.25=0.00032.
iv. P(X≥3)=P(X=3)+P(X=4)+P(X=5)=
=C53p3(1−p)2+C54p4(1−p)1+C55p5(1−p)0=
=10∗0.23∗(1−0.2)2+5∗0.24+(1−0.2)1+0.25=0.05792.
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