Question

5% of manufactured goods resulting from a production is damaged. In this production process, an inspector / inspector inspects the items one by one at random. Calculate the possibility that the inspector found the first item damaged on the 6th inspection.

Answer 1

This is a geometric distribution

P(X=x) =$p(1-p)^{x-1}$

=$0.05*(1-0.05)^{6-1}$

=0.0387

The possibility that the inspector found the first item damaged on the 6th inspection is 3.87%.