5% of manufactured goods resulting from a production is damaged. In this production process, an inspector / inspector inspects the items one by one at random. Calculate the possibility that the inspector found the first item damaged on the 6th inspection.
1
Expert's answer
2020-04-06T17:48:37-0400
This is a geometric distribution
P(X=x) ="p(1-p)^{x-1}"
="0.05*(1-0.05)^{6-1}"
=0.0387
The possibility that the inspector found the first item damaged on the 6th inspection is 3.87%.
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