The following information is provided: The sample size is "N=100," the number of favorable cases is "X=70," and the sample proportion is "\\bar{p}=\\dfrac{X}{N}=\\dfrac{70}{100}=0.7," and the significance level is "\\alpha=0.05"
The following null and alternative hypotheses need to be tested:
"H_0:p=0.75"
"H_1:p\\not=0.75"
This corresponds to a two-tailed test, for which a z-test for one population proportion needs to be used.
Based on the information provided, the significance level is "\\alpha=0.05," and the critical value for a two-tailed test is "z_c=1.96."
The rejection region for this two-tailed test is "R=\\{z:|z|>1.96\\}"
The "z-" statistic is computed as follows:
Since it is observed that "|z|=1.1547<1.96=z_c," it is then concluded that the null hypothesis is not rejected. Therefore, there is not enough evidence to claim that the population proportion "p" is different than "p_0," at the "\\alpha=0.05" significance level.
Using the P-value approach: The p-value for "z=-1.1547" is "p=0.2485," and since "p=0.2485\\geq0.05," it is concluded that the null hypothesis is not rejected. Therefore, there is not enough evidence to claim that the population proportion "p" is different than "p_0," at the "\\alpha=0.05" significance level.
The following statements are wrong:
(3) The value of the test statistic is -1.09.
(4) The p-value is 0.2502.
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