The correct answer is A) If sample size of these multiple samples are increased the mean of these samples tend to be closer to the population mean.
"E=z_{\\alpha\/2}\\frac{\\sigma}{\\sqrt{n}}" is the margin of error.
We see that if sample size increases margin of error decreases.
From here it follows that "n=(\\frac{z_{\\alpha\/2}\\sigma}{E})^2."
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