1)P(Z <?)= 0.5.
The midpoint of a normal distribution curve is at Z=0, the area to the left is equal to the area to the right. 0.5.
The answer is (3) 0
2)P(70.5 <"\\bar x" <71.5)
Mean =70, SD =6, n=36
Z="\\frac {(\\bar x - mean) \\sqrt n} {SD}"
Z1="\\frac {(70.5-70) \\sqrt{36}}{6}"
Z1=0.5
Z2="\\frac {(71.5-70) \\sqrt {36}}{6}"
Z2=1.5
="\\Phi(1.5)-\\Phi(0.5)"
The values are read from a Z-table
=0.93319-0.69146
=0.24173
(4)0.2415
3)P("\\bar x \\geq 67.5)"
Z="\\frac {(67.5-70)\\sqrt {36}} {6}"
Z=-2.5
"\\Phi(-2.5)"
=0.9938
(2)0.9938
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