The probability of a professor receiving a material and adopting = p(receiving material) and p( adopting the material)
=0.8*0.3
=0.24
The probability of a professor adopting the material= p(professor receiving the material and adopting) or p(professor not receiving the material and adopting)
=(0.8*0.3)+(0.2*0.1)
=0.26
The probability that a professor received the material given that he/she adopted it= p(receiving a material and adopting)/p(adopting the material)
=0.24/0.26
Answer
=0.9231
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