Mean = 125 and standard deviation = 24
(a) Probability of student will read more than 130 words per minute:
z score for x = 130 is:
z = (130 - 125)/24 = 0.21
P(x > 130) = P(z > 0.21) = 1-0.5832 = 0.4168 (using standard normal table)
(b) When sample size n = 12,
standard error of mean = 24/ 120.5 = 6.928
z score = (130 - 125)/6.928 = 0.72
P(x > 130) = P(z > 0.72) = 1-0.7642 = 0.2358 (using standard normal table)
(c) When sample size n = 24,
standard error of mean = 24/ 240.5 = 4.899
z score = (130 - 125)/4.899 = 1.02
P(x > 130) = P(z > 1.02) = 1-0.8461= 0.1539 (using standard normal table)
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