Question #91362

Q. Choose the correct answer.
Q. Which of the following statement is true for sequence {(〖-1)〗^(n-1)}?
a. The sequence is bounded
b. The sequence is increasing
c. The sequence is decreasing
d. The sequence is neither increasing nor decreasing

Expert's answer

Answer to Question #91362 - Math - Real Analysis

Question: Choose the correct answer.

Which of the following statement is true for sequence {an=(1)n1}\{a_{n} = (-1)^{n - 1}\}?

a. The sequence is bounded

b. The sequence is increasing

c. The sequence is decreasing

d. The sequence is neither increasing nor decreasing

Solution

The option (a) is Correct.

Explanation

The nth term of the sequence is an=(1)n1a_{n} = (-1)^{n - 1}

Hence the sequence is


a1=(1)11=1,a2=(1)21=1,a3=(1)31=1,a4=(1)41=1a _ {1} = (- 1) ^ {1 - 1} = 1, \quad a _ {2} = (- 1) ^ {2 - 1} = - 1, \quad a _ {3} = (- 1) ^ {3 - 1} = 1, \quad a _ {4} = (- 1) ^ {4 - 1} = - 1 \quad \dots


We can see that for all values of nNn \in \mathbb{N}, there exist two numbers 1 and -1 such that an1a_{n} \leq 1 for all even nn, and an1a_{n} \geq -1 for all odd nn.

The two number 1 and -1 are called lower and upper bound.

Hence the series is bounded above and bounded below.

Bounded Sequences of Real Numbers

A sequence ana_{n} ; n=1,2,3,n = 1,2,3,\ldots of real numbers is said to be Bounded Above if there exists a real number MRM \in \mathbb{R} such that anMa_{n} \leq M for every nNn \in \mathbb{N} . And if for mRm \in \mathbb{R} such that manm \leq a_{n} for every nNn \in \mathbb{N} , the sequence is called Bounded Below.

Taking nn along horizontal and (1)n1\left(-1\right)^{n - 1} along vertical we get the graph as shown by the dots below.



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