Question 1. If (an) and (bn) are Cauchy sequences, show directly that (an+bn) is also a Cauchy sequence.
Solution. Since (an) and (bn) are Cauchy sequences, for any ε>0 there are N1∈N, such that ∣an−am∣<2ε for all m,n>N1, and N2∈N, such that ∣bn−bm∣<2ε for all m,n>N2. Set N=max{N1,N2}. Then for all m,n>N we have
∣(an+bn)−(am+bm)∣=∣an−am+bn−bm∣≤∣an−am∣+∣bn−bm∣<2ε+2ε=ε.
Thus, (an+bn) is a Cauchy sequence.