Question 1. Let x1=a>0 and xn+1=xn+1/xn. Show that xn diverges.
Solution. Suppose there is b=limxn<∞. Note that b>0, because x1>0 and (xn) is increasing. Then consider the equality xn+1=xn+1/xn. As n→∞ the left-hand side of this equality tends to b, while the right-hand side tends to b+1/b. Since b=b+1/b, we obtain a contradiction.