Question #7809

Using the binomial theorem, find the limit of Sn=(1+1/n)^n-1

Expert's answer

limn[(1+1n)n1]=limn(1+1n)n1=[1n]1=elimnn(1+1n1)n1=elimnn(1n)n1=e1.\lim_{n \to \infty} \left[ \left(1 + \frac{1}{n}\right)^n - 1 \right] = \lim_{n \to \infty} \left(1 + \frac{1}{n}\right)^n - 1 = \left[1^n \right] - 1 = e^{\lim_{n \to \infty} \frac{n \left(1 + \frac{1}{n} - 1\right)}{n}} - 1 = e^{\lim_{n \to \infty} \frac{n \left( \frac{1}{n} \right)}{n}} - 1 = e - 1.


Answer: e1e - 1.

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