Question #69118

true/false? prove..
Every function differentiable on [a, b] is bounded on [a, b]

Expert's answer

Answer on Question #69118 – Math – Real Analysis

Question

True/false? Prove.

Every function differentiable on [a,b][a, b] is bounded on [a,b][a, b].

Solution

Let us start from the fact that if function ff is differentiable at x0x_0 then ff is continuous at x0x_0 (see https://proofwiki.org/wiki/Differentiable_Function_is_Continuous).

Since function ff is differentiable on [a,b][a, b] (i.e. ff is differentiable at any x0[a,b]x_0 \in [a, b]) then ff is continuous at any x0[a,b]x_0 \in [a, b], i.e. ff is continuous on [a,b][a, b].

Since ff is continuous on [a,b][a, b] then ff is bounded on [a,b][a, b] (see http://www-history.mcs.st-and.ac.uk/~john/analysis/Lectures/L21.html).

Answer: True.

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