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Answer to Question #69111 in Real Analysis for kapil
Question #69111
Show that the function f :[0, 1] → R defined by
f(x)= { 1, when x is rational ; 2 when x is irrational
is not Riemann integrable.
f(x)= { 1, when x is rational ; 2 when x is irrational
is not Riemann integrable.
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