Question #64863

Verify Inverse function theorem for finding the derivative at a point y of the 0
domain of the inverse function of the function f (x) = cosx, x ∈[0,π].Hence, find
the derivative of the inverse function aty

Expert's answer

Answer on Question #64863 – Math – Real Analysis

Question

Verify Inverse function theorem for finding the derivative at a point yy of the 0 domain of the inverse function of the function f(x)=cosx,x[0,π]f(x) = \cos x, x \in [0, \pi]. Hence, find the derivative of the inverse function at yy.

Solution

Derivative of the Inverse Function:


ddxf1(x)=1f(f1(x)).\frac{d}{dx} f^{-1}(x) = \frac{1}{f'(f^{-1}(x))}.f(x)=cosx,f(x)=sinx,f1(x)=arccosx.f(x) = \cos x, \quad f'(x) = -\sin x, \quad f^{-1}(x) = \arccos x.y=f(x)=0 when x=π2.y = f(x) = 0 \text{ when } x = \frac{\pi}{2}.


Thus


ddxf1(x)x=0=1sin(arccos(0))=1sin(π2)=1.\frac{d}{dx} f^{-1}(x)|_{x=0} = \frac{1}{-\sin(\arccos(0))} = -\frac{1}{\sin\left(\frac{\pi}{2}\right)} = -1.


Answer: 1-1.

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