The f:[ 3,13] to R defined by f(x)= [ x-3]- 13 is continuous function. True or false with full explanation
We have
f(4−0)=0−13=−13f(4)=1−13=−12f(4−0)≠f(4)f(4-0)=0-13=-13\\ f(4)=1-13=-12\\ f(4-0)\ne f(4)f(4−0)=0−13=−13f(4)=1−13=−12f(4−0)=f(4)
Thus f is not continuous in x=4, hence it is not continuous on [3,13]
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