Show that the union of two sets, each of measure zero, has measure zero
By monotonicity and non-negativity of the measure: Let μA=0, μB=0\mu A=0,\ \mu B=0μA=0, μB=0:
0≤μ(A∪B)≤μA+μB=0⇒μ(A∪B)=00\leq\mu(A\cup B)\leq\mu A+\mu B=0\Rightarrow\mu(A\cup B)=00≤μ(A∪B)≤μA+μB=0⇒μ(A∪B)=0
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments