Question #302341

The function f(x)= [x]- x is not integrable in [ 0,3] , where [ x] denote greatest integer function.





True or false with full explanation

1
Expert's answer
2022-02-25T07:49:38-0500

We remind that the function [x][x] has on the interval [0,3][0,3] the following form: [x]=0,[x]=0, 0x10\leq x\leq1, [x]=1,1x2[x]=1,1\leq x\leq2, [x]=2,2x3[x]=2,2\leq x\leq3. It is clear that the function f(x)=[x]xf(x)=[x]-x is integrable on intervals [0,1],[1,2][0,1],[1,2] and [2,3][2,3]. Thus the function x[x]x-[x] is integrable on the interval[0,3][0,3], because it is bounded and has finitely many points of discontinuity.


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