Question #299948

The function f(x)= [x]- x is not integrable in [ 0,3] , where [ x] denote greatest integer function.


True or false with full explanation

1
Expert's answer
2022-02-21T16:03:29-0500

f(x)=xx=0,f(x)=x-x=0, if x[0,1).x\in [0,1).

f(x)=(x1)x=1,f(x)=(x-1)-x=-1, if x[1,2).x\in [1,2).

f(x)=(x2)x=2,f(x)=(x-2)-x=-2, if x[2,3).x\in [2,3).

Therefore, the set of discontinuity of the function f(x) is {1,2,3}\{1,2,3\}. This set is finite, hence, its mearuse is 0. By Lebesque's criterion of integrability, the function f(x) is integrable.


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