Question #299118

Find


lim tan x sec^2 x- x/x^3


x→0

1
Expert's answer
2022-02-18T15:00:15-0500
limx0tanxsec2xxx3=limx0(tanxsec2xx)(x3)\lim\limits_{x\to0}\dfrac{\tan x\sec^2 x-x}{x^3}=\lim\limits_{x\to0}\dfrac{(\tan x\sec^2 x-x)'}{(x^3)'}

=limx0sec4x+2tan2xsec2x13x2=\lim\limits_{x\to0}\dfrac{\sec^4 x+2\tan^2 x\sec^2 x-1}{3x^2}

=limx0sec2x(1+tan2x)+2tan2xsec2x13x2=\lim\limits_{x\to0}\dfrac{\sec^2 x(1+\tan ^2 x)+2\tan^2 x\sec^2 x-1}{3x^2}

=limx0tan2x+3tan2xsec2x3x2=\lim\limits_{x\to0}\dfrac{\tan ^2 x+3\tan^2 x\sec^2 x}{3x^2}

=13limx0tan2xx2+33limx0tan2xx2(limx0sec2x)=\dfrac{1}{3}\lim\limits_{x\to0}\dfrac{\tan ^2 x}{x^2}+\dfrac{3}{3}\lim\limits_{x\to0}\dfrac{\tan ^2 x}{x^2}(\lim\limits_{x\to0}\sec^2 x)

=13(1)+1(1)=43=\dfrac{1}{3}(1)+1(1)=\dfrac{4}{3}


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