If a>0 then show that Lin(1/1+na)=0
"\\lim_{n\\rightarrow \\infty} (\\dfrac{1}{1+na})\n\\\\=\\lim_{n\\rightarrow \\infty} (\\dfrac{1}{1+\\infty .a})\n\\\\=\\lim_{n\\rightarrow \\infty} (\\dfrac{1}{\\infty})\n\\\\=0"
Hence, proved.
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