Let 𝑥𝑘 be a Cauchy sequence and 𝑓 be a continuous function, show that 𝑓(𝑥𝑘) is also a Cauchy sequence.
It is false.
Example:
Take
X=(0,+∞)xk=1kf:x↦1x\begin{gathered} X=(0,+\infty) \\ x_{k}=\frac{1}{k} \\ f: x \mapsto \frac{1}{x} \end{gathered}X=(0,+∞)xk=k1f:x↦x1
(xk)\left(x_{k}\right)(xk) is Cauchy
f is continuous
f(xk)=kf\left(x_{k}\right)=kf(xk)=k is not Cauchy
Given statement will be true if f is UNIFORMLY CONTINUOUS.
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