2000for 5%years with interest rate 12% compounded montly
Solution;
Given;
P=2000
t=5
"j=\\frac{0.12}{12}=0.01"
"n=5(12)=60"
m=12
i=0.12
Hence;
"A=P[\\frac{1-(1+j)^{-n}}{j}]"
"A=2000[\\frac{1-(1+0.01)^{-60}}{0.01}]"
"A=2000(44.9555)"
"A=89,910.08"
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