2000for 5%years with interest rate 12% compounded montly
Solution;
Given;
P=2000
t=5
j=0.1212=0.01j=\frac{0.12}{12}=0.01j=120.12=0.01
n=5(12)=60n=5(12)=60n=5(12)=60
m=12
i=0.12
Hence;
A=P[1−(1+j)−nj]A=P[\frac{1-(1+j)^{-n}}{j}]A=P[j1−(1+j)−n]
A=2000[1−(1+0.01)−600.01]A=2000[\frac{1-(1+0.01)^{-60}}{0.01}]A=2000[0.011−(1+0.01)−60]
A=2000(44.9555)A=2000(44.9555)A=2000(44.9555)
A=89,910.08A=89,910.08A=89,910.08
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