Question #273033

2000for 5%years with interest rate 12% compounded montly

1
Expert's answer
2021-11-30T04:26:17-0500

Solution;

Given;

P=2000

t=5

j=0.1212=0.01j=\frac{0.12}{12}=0.01

n=5(12)=60n=5(12)=60

m=12

i=0.12

Hence;

A=P[1(1+j)nj]A=P[\frac{1-(1+j)^{-n}}{j}]

A=2000[1(1+0.01)600.01]A=2000[\frac{1-(1+0.01)^{-60}}{0.01}]

A=2000(44.9555)A=2000(44.9555)

A=89,910.08A=89,910.08





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