limn→0(2nn2+1)Divide each term in the limit above by the highest power of n (n2) to obtainlimn→0(2n1+1n2)Which is 0\displaystyle \lim_{n \to 0}(\frac{2n}{n^2+1})\\ \text{Divide each term in the limit above by the highest power of n $(n^2)$ to obtain}\\ \lim_{n \to 0}(\frac{\frac{2}{n}}{1+\frac{1}{n^2}})\\ \text{Which is 0}n→0lim(n2+12n)Divide each term in the limit above by the highest power of n (n2) to obtainn→0lim(1+n21n2)Which is 0
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