A−B={x:xϵA,xϵB}A-B=\{x:x\epsilon A,x\cancel{\epsilon}B\}A−B={x:xϵA,xϵB}
Let A={1,2,3,4}A=\{1,2,3,4\}A={1,2,3,4}
B={3,4,5,6}B=\{3,4,5,6\}B={3,4,5,6}
A−B={1,2}A-B=\{1,2\}A−B={1,2}
(A−B)UB={1,2}U{3,4,5,6}(A-B)UB=\{1,2\}U\{3,4,5,6\}(A−B)UB={1,2}U{3,4,5,6}
={1,2,3,4,5,6}=\{1,2,3,4,5,6\}={1,2,3,4,5,6}
≠{1,2,3,4}=A\not =\{1,2,3,4\}=A={1,2,3,4}=A
∴(A−B)UB≠A\therefore (A-B)UB\not =A∴(A−B)UB=A
So the given statement is false.
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