If the equation F(x,y) =0 is written out in full terms of the coordinates, it will look like below
F1(x1,...,xi,y1,...,yi)=0
F2(x1,...,xi,y1,...,yi)=0
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Fi(x1,...,xi,y1,...,yi)=0.
If Ri+1→Ri then dxF is the differential of the function Ri+1 to Ri obtained by fixing and
∂F/∂x is the corresponding Jacobi matrix , thus
∂x∂F=[∂x1∂F1∂x1∂Fi∂xi∂F1∂xi∂Fi]
Letting Ri+1→Ri be Ci at a point (a,b) with F(a,b)=0. If dxF(a,b) is invertible , there are positive numbers € and 𝛿
a) If ∣x−a∣<δ then there is one and only one point y=φ(x) satisfying ∣x−b∣<€ and F(x,y)=0
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