Question #20326

If f is continuous on [a, b] and integral a to b of f(x)g(x)dx=0 for all continuous functions g on [a, b] then f is identically equal to 0 on [a, b]

Expert's answer

Conditions

If ff is continuous on [a,b][a, b] and integral aa to bb of f(x)g(x)dx=0f(x)g(x)dx=0 for all continuous functions gg on [a,b][a, b] then ff is identically equal to 0 on [a,b][a, b]

Solution

This is not true. Consider the counterexample:


f(x)=sinxf(x) = \sin xg(x)=1g(x) = 1x[a,b]=[0,2π]x \in [a, b] = [0, 2\pi]


Then f,gf, g are continuous on [a,b][a, b] and


02πsinxdx=0\int_{0}^{2\pi} \sin x \, dx = 0


but


f(x)=sinx0x[0,2π]f(x) = \sin x \neq 0 \quad \forall x \in [0, 2\pi]

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