Question #200129

Show that the 2^n is not convergent.


1
Expert's answer
2021-05-31T08:10:16-0400

Solution:

We know that a necessary and sufficient condition for the convergence of a sequence is that it is bounded and has a unique limit point.

2n=(1+1)n1+n,nN2^{n}=(1+1)^{n} \geq 1+n, \forall n \in \mathbb{N}

If P>0 is any real number howsoever large, we have,

1+n>P, whenever n>P-1 .

Let m be a positive integer, such that, m>P-1.

\Rightarrow For any real number P>0, \exists a positive integer, m, such that 2n>P,nm2^{n}>P, \forall n \geq m

\Rightarrow The sequence {2n}\left\{2^{n}\right\} is not bounded.

\Rightarrow The sequence {2n}\left\{2^{n}\right\} diverges to \infty .

\Rightarrow The sequence {2n}\left\{2^{n}\right\} is not convergent.

Hence, proved.


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