Is f(x)=1/x2/3 in L3[1 2] ?
for L3[1 2] :
∫12∣f(x)∣3dx<∞\int^2_1|f(x)|^3dx<\infin∫12∣f(x)∣3dx<∞
then we have:
∫12x−2dx=−1/x∣12=−1/2+1=1/2<∞\int^2_1x^{-2}dx=-1/x|^2_1=-1/2+1=1/2<\infin∫12x−2dx=−1/x∣12=−1/2+1=1/2<∞
so, f(x)=1/x2/3 in L3[1 2]
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