Question #19347

how to prove this equation A∩B⊂A⊂A⊂B

Expert's answer

Conditions

how to prove this equation ABAABA \cap B \subset A \subset A \subset B

Solution

First of all there should be a little mistake, I think the correct conditions is how to prove:


(AB)A(AB)(A \cap B) \subset A \subset (A \cup B)


Let's prove first:


(AB)A(A \cap B) \subset A


As we know, the elements from (AB)(A \cap B) are those elements, which are belong as to AA as to BB .

That's why each of these elements is in A, but if we take some element from A, but which is not in B, so it will not be in (AB)(A \cap B) . That's why (AB)A(A \cap B) \subset A .

Now let's prove:


A(AB)A \subset (A \cup B)


As we know, the elements from (AB)(\mathbf{A} \cup \mathbf{B}) are those elements, which are belong to A or to B. Consider 2 sets A and B, which have not common points. For any element of A, it is belong to (AB)(\mathbf{A} \cup \mathbf{B}) , but let's take an element from B, it's not in A, but in (AB)(\mathbf{A} \cup \mathbf{B}) . That's why A(AB)\mathbf{A} \subset (\mathbf{A} \cup \mathbf{B})

Q.E.D.

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