Question #191288

Show that the function f :R -> R defined by f(x) = 2x+ 7 has an inverse by applying the inverse function theorem. Find its inverse also 


1
Expert's answer
2021-05-11T07:01:12-0400

We have given the function,


f:RRf: R \rightarrow R defined by f(x)=2x+7f(x) = 2x+7


Since, the given function is bijective because for every y there exist a unique x


x=y77x = \dfrac{y-7}{7} , such that f(x)=yf(x) = y


In general we can say that RRR \rightarrow R


f(x)=ax+b,a0f(x) = ax+b, a \ne 0


Hence, we can say that inverse exist for the given function f(x)f(x).


Calculation of f1(x).f^{-1}(x).


f(x)=2x+7f(x)= 2x+7


y=2x+7y = 2x+7


x=y72x = \dfrac{y-7}{2}


where, x=f1(x).x = f^{-1}(x).


Hence, f1(x)=y72.f^{-1}(x) = \dfrac{y-7}{2}.


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