Answer to Question #184021 in Real Analysis for Tulela

Question #184021

If a is a sequence of real numbers, then

△a = (an+1 − an)N

is called the difference sequence of a.

a) Let a be a sequence of real numbers. Find △2a := △(△a)


 b) If a is a convergent sequence of real numbers, prove that △a is a null se- quence.


1
Expert's answer
2021-05-07T09:06:56-0400

an=(an+1an)△a_n = (a_{n+1} − a_n)


(a) 2a=Δan+1Δan△^2a=\Delta a_{n+1}-\Delta a_n

=(an+2an+1)(an+1an)=an+22an+1+an=(a_{n+2}-a_{n+1})-(a_{n+1}-a_n)\\=a_{n+2}-2a_{n+1}+a_n

(b) a is a convergent sequence of real numbers

Then the value of a is finite, Hence Δa\Delta a is null sequence.


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