Show that if lim a_n = negative infinity, the lim 1/a_n = 0.
1
Expert's answer
2012-11-07T09:43:17-0500
Suppose lim a_n = - infinity. We should prove that lim 1/a_n = 0. Fix any epsilon>0 and take A = 1/epsilon. Since lim a_n = - infinity, there exists N such that forall n>N we have that a_n < -A
Therefore |a_n| > A
|1/a_n| < 1/A =epsilon.
Thus for all n>N |1/a_n| <epsilon. This means that lim 1/a_n = 0.
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