Question #175356

If a sequence is bounded, then it has at least two convergent subsequences. Check whether the given statement is true of false. Give a counterexample in support of your answer.


1
Expert's answer
2021-04-29T17:59:28-0400

Let a1,a2,a_1,a_2,… be a bounded sequence in R\R that does not converge.


Let ​sns_n be a bounded sequence in R\R that does not converge. Then by the Bolzano Weierstrass theorem there exists a subsequence, snks_{n_k}, that converges. Let a be the limit of snks_{n_k}​​. By definition sns_n does not converge so it can not converge to a. That is, there exists ϵ>0ϵ>0 such that for all NRN∈\R, there exists n>Nn>N such that snaϵ∣s_n​−a∣≥ϵ. So there exists a sequence sms_m​ that is a subsequence of sns_n​ with m>Nm>N. By its definition sms_m does not have a subsequence that converges to a. However, sms_m is bounded because sns_n is bounded. So by the Bolzano Weierstrass theorem there exists a subsequence, smjs_{m_j}, that converges.


Clearly smjs_{m_j} does not converge to a.


\therefore The statement is Fa.lse.


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