Answer to Question #170526 in Real Analysis for Prathibha Rose

Question #170526

Let D be convex and open in R2 and let f:D to R be convex .let [a,b] ×[c,d] be a closed rectangle contained in D ,where a,b,c,d element R with a<b and c<d .prove that there exists k element of R such that ,

|f(x,y)-f(u,v)|<k (|x-u|+|y-v|) for all ((x,y);(u,v)) element of

[a,b]×[c,d].


1
Expert's answer
2021-03-26T08:47:53-0400

Since D is convex and open, "f" being a convex function satisfies local Lipschitz condition and hence continuous. So in particular "f" is continuous on the rectangle. Hence it is continuous on a compact set. So is the function "((x,y),(u,v))\\mapsto\\frac{|f(x,y)-f(u,v)|}{|x-u|+|y-v|}." Hence continuous image being compact, its image is compact in "\\mathbb{R}" and hence bounded. We take "k" as the bound.


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