Question #12526

Find Laplace transform F(p) for function S(t) - sin-Frenele integral

Expert's answer

S(t)=0tsinu2πudu=[v=u2]=2π0tsin(v2)dvS(t) = \int_0^t \frac{\sin u}{\sqrt{2\pi u}} \, du = \left[ v = u^2 \right] = \sqrt{\frac{2}{\pi}} \int_0^{\sqrt{t}} \sin\left(v^2\right) dvS(0)=0S(0) = 00sin(v2)dv=12π2\int_0^\infty \sin(v^2) \, dv = \frac{1}{2} \sqrt{\frac{\pi}{2}}S()=1/2S(\infty) = 1/2


By integration theorem:


S(t)p2+1p2pp2+1S(t) \rightarrow \frac{\sqrt{\sqrt{p^2 + 1 - p}}}{2p\sqrt{p^2 + 1}}

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