Question #12321

Find integral: int(dz/z) on curve C={z=x+iy| abs(z)=1, y>=0}

Expert's answer

z=eitz = e^{it}Cdzz=0πieiteitdt=0πidt=πi\int_{C} \frac{dz}{z} = \int_{0}^{\pi} \frac{ie^{it}}{e^{it}} dt = \int_{0}^{\pi} idt = \pi i

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