Question #122938
Show that {fn}, where fn : [0, 1] → R is the map fn(x) = x
n, is not uniformly convergent.
1
Expert's answer
2020-06-22T17:32:05-0400

Given fn: [0,1]Rf_n: \ [0,1] \to R such that fn(x)=xnf_n(x) =x^n .

Now, Pointwise convergence is limnfn(x)=limnxn={0 if x[0,1)1 if x=1\lim_{n\to \infin} f_n(x) = \lim_{n\to \infin} x^n = \begin{cases} 0 \ if \ x\in[0,1) \\ 1 \ if \ x=1 \end{cases} .

Each fn(x)=xnf_n(x) =x^n is continuous for every n but it's pointwise limit is not continuous. So fn(x)f_n(x) is not uniformly convergent.


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